考虑一个三维谐振子。这给出在第一、二层的核壳层(“l”是角量子数,对于质子或中子能量的影响力是主量子数的一半)
level n | l | ml | ms |
---|---|---|---|
0 | 0 | 0 | 1⁄2 |
−1⁄2 | |||
1 | 1 | 1 | 1⁄2 |
−1⁄2 | |||
0 | 1⁄2 | ||
−1⁄2 | |||
−1 | 1⁄2 | ||
−1⁄2 |
我们可以想像自己建立一个原子核,并开始对它加入质子和中子。质子和中子必会从能量较低的能级开始填入,因此,头两个质子先填入第0能级,下6个质子则填第一能级,依此类推。
在三维谐振子中,每个能级可填入的核子数量如为,由于自旋的简并性是加倍
因此
对所有的整数k,给出了以下的幻数2,8,20,40,70,112...
前六个能级是
level 0: 2 states (l = 0) = 2.
level 1: 6 states (l = 1) = 6.
level 2: 2 states (l = 0) + 10 states (l = 2) = 12.
level 3: 6 states (l = 1) + 14 states (l = 3) = 20.
level 4: 2 states (l = 0) + 10 states (l = 2) + 18 states (l = 4) = 30.
level 5: 6 states (l = 1) + 14 states (l = 3) + 22 states (l = 5) = 42.
level n | l | ml | ms |
---|---|---|---|
0 | 0 | 0 | 1⁄2 |
−1⁄2 | |||
1 | 1 | 1 | 1⁄2 |
−1⁄2 | |||
0 | 1⁄2 | ||
−1⁄2 | |||
−1 | 1⁄2 | ||
−1⁄2 |
level 0 (n=0): 2 states (j = 1⁄2). 奇数对
level 1 (n=1): 2 states (j = 1⁄2) + 4 states (j = 3⁄2) = 6. 偶数对
level 2 (n=2): 2 states (j = 1⁄2) + 4 states (j = 3⁄2) + 6 states (j = 5⁄2) = 12. 奇数对
level 3 (n=3): 2 states (j = 1⁄2) + 4 states (j = 3⁄2) + 6 states (j = 5⁄2) + 8 states (j = 7⁄2) = 20. 偶数对
level 4 (n=4): 2 states (j = 1⁄2) + 4 states (j = 3⁄2) + 6 states (j = 5⁄2) + 8 states (j = 7⁄2) + 10 states (j = 9⁄2) = 30. 奇数对
level 5 (n=5): 2 states (j = 1⁄2) + 4 states (j = 3⁄2) + 6 states (j = 5⁄2) + 8 states (j = 7⁄2) + 10 states (j = 9⁄2) + 12 states (j = 11⁄2) = 42. 偶数对